UARM Calculator
Uniformly Accelerated Rectilinear Motion: calculate final velocity and distance travelled.
Uniformly Accelerated Rectilinear Motion (UARM) describes the motion of an object moving in a straight line with constant acceleration. It is the model that describes free fall, vertical throws and the motion of vehicles that accelerate or brake uniformly. The UARM equations allow the velocity at any instant and the distance travelled to be calculated.
This calculator solves UARM given the initial velocity, acceleration and time values. It calculates the final velocity and distance covered, and generates a graph of velocity and position over time. The acceleration can be positive (the object accelerates) or negative (the object decelerates or moves in the opposite direction).
Can be negative (opposite direction)
Can be negative (deceleration)
What is UARM?
Uniformly Accelerated Rectilinear Motion (UARM) is the motion in which an object moves in a straight line with constant acceleration. The velocity changes uniformly over time.
v(t) = v₀ + a · t
d(t) = v₀ · t + ½ · a · t²
v² = v₀² + 2 · a · d
The three UARM equations and when to use each
UARM is described by three equations derived from one another. The first, v = v₀ + a·t, relates velocity to time and is used when you want to know how fast the object is moving at a given instant. The second, d = v₀·t + ½·a·t², gives the distance travelled as a function of time and is the one that appears in most free-fall problems. The third, v² = v₀² + 2·a·d, is especially useful because it does not include time: it relates velocity and distance directly, which is very handy in braking problems where time is neither known nor asked for. Choosing the right equation is the step that saves the most time when solving an exercise.
Worked example
A car travels at 20 m/s and brakes with a constant acceleration of −4 m/s². How long does it take to stop and how far does it travel? For the time we use v = v₀ + a·t with v = 0: 0 = 20 + (−4)·t, giving t = 5 s. For the distance the third equation is better, as it does not depend on time: v² = v₀² + 2·a·d → 0 = 400 + 2·(−4)·d → d = 400/8 = 50 m. The car covers 50 metres before stopping, which explains why braking distance grows so quickly with speed: since it depends on v², doubling the speed quadruples the distance.
Gravitational acceleration on different bodies
| Celestial body | Gravity (m/s²) |
|---|---|
| Moon | 1,62 |
| Mars | 3,72 |
| Venus | 8,87 |
| Earth | 9,81 |
| Jupiter | 24,79 |
| Sun | 274 |
How to read UARM graphs
In UARM the graph of velocity against time is a straight line whose slope is the acceleration: rising if the object speeds up and falling if it brakes. The area under that line equals the distance travelled, a very useful trick for solving problems graphically. The position-time graph, by contrast, is a parabola: curvature upwards indicates positive acceleration and downwards, deceleration. If the parabola reaches a maximum and then descends, it means the object stopped and reversed direction, as happens in a vertical throw when the ball reaches its highest point.